Do not peek if you are still calculating: http://www.math.ucla.edu/~pak/lectures/Cat/pakcat.htm
― How I Wrote Matchstick Men (James Redd and the Blecchs), Sunday, 5 July 2015 21:58 (ten years ago)
sorry i've been slacking on serving up with the answer, i'm trying to get a detail right and the friend who told me these riddles isn't responding. be back very soon with a fully satisfying proof
― flopson, Sunday, 5 July 2015 22:52 (ten years ago)
I liked this particular write-up: http://www.math.ku.edu/~jmartin/courses/math724-F13/count-dyck.pdf
― How I Wrote Matchstick Men (James Redd and the Blecchs), Sunday, 5 July 2015 23:12 (ten years ago)
oh hah! once you see the pun it all follows (well, 2b does). here is something that i think is not too terrible a hint. write "i get a dollar" as "(" (open paren) and "i give a dollar" as ")" (closed paren). now consider what "allowable" sequences look like syntactically in such a translation :-)
― got bent (mild cheezed off vibes) (s.clover), Sunday, 5 July 2015 23:42 (ten years ago)
my dad is asking for a good introductory group theory text. nothing too dry.
he is working on this, but i think he finds it dry:
http://www.amazon.com/gp/product/0521312493/
any suggestions?
― the late great, Monday, 13 July 2015 01:45 (ten years ago)
he specifically asked for group theory, so my sense is maybe some of the stuff in that book is over his head and he wants something a little more basic?
― the late great, Monday, 13 July 2015 01:48 (ten years ago)
Kind of an interesting article about the Navier-Stokes equations, which tormented me in my days as a Mechanical Engineering student:
https://www.quantamagazine.org/20150721-famous-fluid-equations-are-incomplete/
― o. nate, Thursday, 23 July 2015 02:30 (ten years ago)
still looking for a group theory book
― the late great, Thursday, 23 July 2015 02:40 (ten years ago)
Try Springer undergrad book by Armstrong.
(Xp)Interesting. Will read later hopefully
― Archaic Buster Poindexter, Live At The Apollo (James Redd and the Blecchs), Thursday, 23 July 2015 02:44 (ten years ago)
Μ. Α. Armstrong, Groups and Symmetry. His topology book seems to be pretty good as well.
― Archaic Buster Poindexter, Live At The Apollo (James Redd and the Blecchs), Thursday, 23 July 2015 03:04 (ten years ago)
^that's probably a good rec. i read his topo book, very fun. iirc there's a good chapter in coxeter's geometry textbook. group theory can't be learned without reference to geometry/symmetry imo. i learnt groups from a number theorist, took years to undo the damage
― flopson, Thursday, 23 July 2015 03:44 (ten years ago)
Lol. Yes, he does the basic symmetry ideas early on and then leads to stuff like orbits and stabilizers in the second half.
― Archaic Buster Poindexter, Live At The Apollo (James Redd and the Blecchs), Thursday, 23 July 2015 03:50 (ten years ago)
Book we used in college was Jacobsen, probably a little too abstract for most tastes. Teacher was awesome though, Jonathan Rogawski (RIP), who was a student of Langlands himself.
― Archaic Buster Poindexter, Live At The Apollo (James Redd and the Blecchs), Thursday, 23 July 2015 03:56 (ten years ago)
Just glanced at Armstrong again. Really touches on a lot of good, interesting stuff in a nice way, such as the kind of group theory and linear algebra that physicists use, or the free group- as seen in topology! - as opposed to a Hard Algebra approach, say, in which you might spend a lot more time on rings and monoids. His topology book comes highly recommended in The Princeton Companion by this guy: http://www.math.ucla.edu/~totaro/
― Archaic Buster Poindexter, Live At The Apollo (James Redd and the Blecchs), Thursday, 23 July 2015 10:56 (ten years ago)
thx for the recommend ... just grabbed the .djvu of "groups and symmetry" and also his (?) "basic topology" too
― the late great, Thursday, 23 July 2015 15:45 (ten years ago)
http://web.math.princeton.edu/generals/examiner.html
princeton oral math exams
some nice questions in there
If f_n is a seqeunce of integrable functions, when is int(f_n)convergent? Can you give an example where this fails?
Set a(n) = 1/n + ... + 1/2n. Compute lim a(n) as n --> infinity.
Let En be a sequence of measurable sets in [0,1] with m(En) --> 1. Doesthere exist a subsequence whose intersections all have measure > 1/2?
― flopson, Saturday, 1 August 2015 23:24 (ten years ago)
sorry for dropping the ball on those combo coin flipping problems. i wanted to write up a nice proof for 2a that everyone could understand but i'm too busy writing a dumbass masters thesis right now. anyways 2a uses reflection principle and for 2b you can find a bijection between unique maximums and multiple maximums by reflecting about the peak /\ in a clever way. the proof of 2b my friend showed me was actually an original one that he's getting published so i prob shouldn't write it here. but i'll link to it later
bonus (easy) analysis question with multiple answers:
find a sequence X_n in R such that lim_{n->infty} X_n - X_{n-1} = 0 but lim_{n->infty} X_n doesn't exist
― flopson, Saturday, 1 August 2015 23:31 (ten years ago)
i think this is 'yes' but cannot prove it
― dead (Lamp), Tuesday, 11 August 2015 01:45 (ten years ago)
after posting and thinking about those for 5 mins i realized none of those questions make sense, i think there's some missing info
like, En = [0,1] for all n is an answer to that one you mention Lamp. m(En) -> 1 and m(Ei int Ej) = 1 > 1/2 for all i, j (taking the sequence itself as subsequence)
― flopson, Tuesday, 11 August 2015 01:59 (ten years ago)
either that or princeton oral exams are a scam
― flopson, Tuesday, 11 August 2015 02:00 (ten years ago)
i need to revisit rudin someday, never got a good handle on measure they/real analysis and ended up doing actuary stuff so having that basis for probability would be valuable if only for exams
― art, Tuesday, 11 August 2015 02:06 (ten years ago)
ilx poster eteaoe convinced me to take measure theory in this very thread. it's ok, a little too dry for me but i didn't pursue stochastic calculus or any of the fancy applications of it, so it mostly just looked like an overly fussy way of doing integration to me at the same. this is my favourite result from measure theory https://en.wikipedia.org/wiki/Borel%E2%80%93Cantelli_lemma which states that
if the sum of probabilities of a random sequence of events is finite, the probability that infinitely many of them occur is zero
― flopson, Tuesday, 11 August 2015 02:20 (ten years ago)
my advisor was super psyched to teach a real analysis class (he was an algebraic topology/knot theory guy) bc he said he felt like he really "got" the subject, but the course was still, as you say, pretty dry. your synopsis is about where i landed, but having gotten into stats since i feel like i shd take another stab.
― art, Tuesday, 11 August 2015 02:34 (ten years ago)
like, En = [0,1] for all n is an answer to that one you mention Lamp.
I took it to mean "is it the case that, for EVERY sequence E_n....."
― Guayaquil (eephus!), Tuesday, 11 August 2015 06:06 (ten years ago)
Once you reach M such that, for m > M, m(Em) > .75 then the maximum disjunction between Em1 and Em2 for m1,m2 > M is strictly less than .25 + .25 = .5 so their intersection has to have measure > 1/2
― Eternal Return To Earth (James Redd and the Blecchs), Tuesday, 11 August 2015 10:29 (ten years ago)
So, any subsequence starting from that point
― Eternal Return To Earth (James Redd and the Blecchs), Tuesday, 11 August 2015 10:30 (ten years ago)
starting from that point on
― Eternal Return To Earth (James Redd and the Blecchs), Tuesday, 11 August 2015 10:43 (ten years ago)
ohhh got it
― flopson, Tuesday, 11 August 2015 14:53 (ten years ago)
hmm ok and since it's cauchy you can always find such a point. might there not be some weird ass measurable sets that would contradict though?
― flopson, Tuesday, 11 August 2015 15:09 (ten years ago)
Don't think you need to bring Cauchy into it, limit is already defined. But I think what is showed is only pairwise intersection, it is possible that out on the tail the intersection of all the sets might have measure < 1/2.
― Eternal Return To Earth (James Redd and the Blecchs), Tuesday, 11 August 2015 16:11 (ten years ago)
we've been working on the questions flopson posted at work and found theres lots of solutions for that question. will post our solution when im back at my desk. kept getting caught up on the wording at first (also read the last > as -->)
― dead (Lamp), Tuesday, 11 August 2015 16:16 (ten years ago)
xp oh right i got limit definitions mixed up
― flopson, Tuesday, 11 August 2015 16:43 (ten years ago)
For countable intersection, calling the subsequence Fi, just go out far enough so that 1- m(F1) < 1/4, 1-m(F2) < 1/8, 1-m(F3) < 1/16, etc.
― Eternal Return To Earth (James Redd and the Blecchs), Tuesday, 11 August 2015 17:24 (ten years ago)
Note also that sets are given to be measurable, so their countable intersection, as it is here, will also be measurable and there will be no weird or wild behavior
― Eternal Return To Earth (James Redd and the Blecchs), Tuesday, 11 August 2015 17:42 (ten years ago)
http://www.lel.ed.ac.uk/~heycock/proof.html
How to prove it
Proof by exampleThe author gives only the case n=2 and suggests that it contains most of the ideas of the general proof.
Proof by intimidation"Trivial"
Proof by vigorous handwavingWorks well in a classroom or seminar setting.
Proof by cumbersome notationBest done with access to at least four alphabets and special symbols.
Proof by exhaustionAn issue or two of a journal devoted to your proof is useful.
Proof by omission"The reader may easily supply the details.""The other 253 cases are analogous.""..."
Proof by obfuscationA long plotless sequence of true and/or meaningless syntactically related statements.
Proof by wishful citationThe author cites the negation, converse, or generalization of a theorem from the literature to support his claim.
Proof by fundingHow could three different government agencies be wrong?
Proof by eminent authority"I saw Karp in the elevator and he said it was probably NP-complete."
Proof by personal communication"Eight-dimensional coloured cycle stripping is NP-complete (Karp, personal communication)."
Proof by reduction to the wrong problem"To see that infinite-dimensional coloured cycle stripping is decidable, we reduce it to the halting problem."
Proof by reference to inaccessible literatureThe author cites a simple corollary of a theorem to be found in a privately circulated memoir of the Slovenian Philological Society, 1883.
Proof by importanceA large body of useful consequences all follow from the proposition in question.
Proof by accumulation of evidenceLong and diligent search has not revealed a counterexample.
Proof by cosmologyThe negation of the proposition is unimaginable or meaningless. Popular for proofs of the existence of God.
Proof by mutual referenceIn reference A, Theorem 5 is said to follow from Theorem 3 in reference B, which is shown to follow from Corollary 6.2 in reference C, which is an easy consequence of Theorem 5 in reference A.
Proof by metaproofA method is given to construct the desired proof. The correctness of the method is proved by any of these techniques.
Proof by pictureA more convincing form of proof by example. Combines well with proof by omission.
Proof by vehement assertionIt is useful to have some kind of authority relation to the audience.
Proof by ghost referenceNothing even remotely resembling the cited theorem appears in the reference given.
Proof by forward referenceReference is usually to a forthcoming paper by the author.
Proof by semantic shiftSome of the standard but inconvenient definitions are changed for the statement of the result.
Proof by appeal to intuitionCloud-shaped drawings frequently help here.
― flopson, Friday, 11 September 2015 17:15 (ten years ago)
http://varianceexplained.org/r/empirical_bayes_baseball/
great stats blog post featuring this striking graph
http://varianceexplained.org/figs/2015-10-01-empirical_bayes_baseball/unnamed-chunk-11-1.png
― flopson, Thursday, 8 October 2015 02:31 (ten years ago)
woaahhh duuudehttps://84c67cd8f568acc648fb74bc321df20db70c2600.googledrive.com/host/0B3p9nx7jwyf9MjFtY3d1aXVBMjA/fourier.gif
― flopson, Saturday, 17 October 2015 20:47 (ten years ago)
can someone explain that to me? i was bad at trig
― flopson, Saturday, 17 October 2015 23:29 (ten years ago)
The Fourier in the URL gives it away, I think. It's an animation on the first 4 orders of fast Fourier approximations of a square wave. You can see it getting closer to pure square wave the further it goes down the page.
― koogs, Sunday, 18 October 2015 02:23 (ten years ago)
New biography of John Horton Conway is out. Same author as the Coxeter bio, rave reviews from all the right people.
― Dover Blecch (James Redd and the Blecchs), Wednesday, 28 October 2015 14:00 (ten years ago)
https://upload.wikimedia.org/wikipedia/commons/0/0f/SquareWaveFourierArrows%2Crotated.gif
― + +, Wednesday, 28 October 2015 16:48 (ten years ago)
some nice riddles from this new ams math grad student blog
http://blogs.ams.org/mathgradblog/2015/12/06/math-puzzlesriddles-part-ii/#more-26560
LIFE ON A CHESSBOARDMost of you are probably familiar with various versions of Conway’s famous “Game of Life”. This riddle pertains to a particularly simple version, played on an 8×8 grid of what are usually envisioned as light-up squares. The setup is as follows: initially, some subset of the squares are lit up (the “starting configuration”). At each stage, a square lights up if at least two of its immediate neighbors (horizontal or vertical) were “on” during the previous stage. Note that in this version of Life, squares do not ever turn from “on” to “off”.It’s easy to see that for the starting configuration in which eight squares along a diagonal of the board are lit up, the entire board is eventually covered by “on” squares. Several other simple starting configurations with eight “on” squares also result in the entire board being covered. Is it possible for a starting configuration with fewer than eight squares to cover the entire board? (If yes, find it; if no, give a proof!)THREE-WAY CAKE SUBDIVISIONA group of three (mutually distrustful) mathematicians are attempting to divide a cake between themselves. They have a knife, but no measuring utensils of any kind. The mathematicians need to agree on a procedure for subdividing the cake in which each mathematician has a role in the subdivision and assignment of cake pieces. This procedure must satisfy the following “fairness” condition: for each mathematician X, if X has “perfect play”, then X can guarantee him or herself at least one-third of the cake, regardless of the actions of the other two mathematicians.In the two-person case, a solution is furnished by the following simple procedure: one person (either one) cuts the cake into two pieces. The other person then chooses a piece for him or herself, with the remaining piece going to the one who originally divided the cake. This procedure evidently satisfies the fairness condition (with one-third replaced by one-half); the question is then to devise a suitable procedure for three mathematicians (or any number of mathematicians, if you are feeling bold!).Note that one is not allowed to assume anything about the other players, even rational self-interest or perfect play on their part. For example, one (flawed) procedure might be to have person A cut the cake into three pieces, and then have A, B, and C then choose their own pieces in some order with A going last (say B, C, and then A). Although one might argue that A has an incentive to divide the cake as equally as possible (since it seems likely that A would receive the smallest piece), we do not assume that A can or will do so. Thus A might (perhaps by accident) cut the cake lopsidedly into one large and two extremely small pieces, violating the fairness condition from the point of view of C.
Most of you are probably familiar with various versions of Conway’s famous “Game of Life”. This riddle pertains to a particularly simple version, played on an 8×8 grid of what are usually envisioned as light-up squares. The setup is as follows: initially, some subset of the squares are lit up (the “starting configuration”). At each stage, a square lights up if at least two of its immediate neighbors (horizontal or vertical) were “on” during the previous stage. Note that in this version of Life, squares do not ever turn from “on” to “off”.
It’s easy to see that for the starting configuration in which eight squares along a diagonal of the board are lit up, the entire board is eventually covered by “on” squares. Several other simple starting configurations with eight “on” squares also result in the entire board being covered. Is it possible for a starting configuration with fewer than eight squares to cover the entire board? (If yes, find it; if no, give a proof!)
THREE-WAY CAKE SUBDIVISION
A group of three (mutually distrustful) mathematicians are attempting to divide a cake between themselves. They have a knife, but no measuring utensils of any kind. The mathematicians need to agree on a procedure for subdividing the cake in which each mathematician has a role in the subdivision and assignment of cake pieces. This procedure must satisfy the following “fairness” condition: for each mathematician X, if X has “perfect play”, then X can guarantee him or herself at least one-third of the cake, regardless of the actions of the other two mathematicians.
In the two-person case, a solution is furnished by the following simple procedure: one person (either one) cuts the cake into two pieces. The other person then chooses a piece for him or herself, with the remaining piece going to the one who originally divided the cake. This procedure evidently satisfies the fairness condition (with one-third replaced by one-half); the question is then to devise a suitable procedure for three mathematicians (or any number of mathematicians, if you are feeling bold!).
Note that one is not allowed to assume anything about the other players, even rational self-interest or perfect play on their part. For example, one (flawed) procedure might be to have person A cut the cake into three pieces, and then have A, B, and C then choose their own pieces in some order with A going last (say B, C, and then A). Although one might argue that A has an incentive to divide the cake as equally as possible (since it seems likely that A would receive the smallest piece), we do not assume that A can or will do so. Thus A might (perhaps by accident) cut the cake lopsidedly into one large and two extremely small pieces, violating the fairness condition from the point of view of C.
― flopson, Friday, 18 December 2015 18:20 (ten years ago)
The cake eating one is particularly badly posed, at first I thought it was Vickrey Clarke Groves but I'm not even sure what the question is
― flopson, Saturday, 19 December 2015 01:27 (ten years ago)
holy shit, springer made basically all its math books (at least) older than 10 years old available online free. the entire graduate texts in mathematics series (including like lang's algebra, whitehead on homotopy theory, thurston on singular homology), the entire lecture notes in mathematics series, the entire universitext series, and much else besides.
this is such a trove of amazing stuff.
― big WHOIS aka the nameserver (s.clover), Monday, 28 December 2015 08:33 (ten years ago)
(lots of philmath stuff too from the synthese series, including great books by beth, etc).
― big WHOIS aka the nameserver (s.clover), Monday, 28 December 2015 08:34 (ten years ago)
what?!?
― Die Angst des Elfmans beim Torschluss (James Redd and the Blecchs), Monday, 28 December 2015 12:23 (ten years ago)
You sure you don't need jstor or university library account or something to access?
― Die Angst des Elfmans beim Torschluss (James Redd and the Blecchs), Monday, 28 December 2015 12:26 (ten years ago)
If not, please provide link.
― Die Angst des Elfmans beim Torschluss (James Redd and the Blecchs), Monday, 28 December 2015 12:27 (ten years ago)
http://link.springer.com/search?facet-series=%22136%22&facet-content-type=%22Book%22&showAll=false
― j., Monday, 28 December 2015 13:13 (ten years ago)
fantastic
― flopson, Monday, 28 December 2015 18:39 (ten years ago)